7+5[1+2(2x+5)]=6(x+7)

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Solution for 7+5[1+2(2x+5)]=6(x+7) equation:


Simplifying
7 + 5[1 + 2(2x + 5)] = 6(x + 7)

Reorder the terms:
7 + 5[1 + 2(5 + 2x)] = 6(x + 7)
7 + 5[1 + (5 * 2 + 2x * 2)] = 6(x + 7)
7 + 5[1 + (10 + 4x)] = 6(x + 7)

Combine like terms: 1 + 10 = 11
7 + 5[11 + 4x] = 6(x + 7)
7 + [11 * 5 + 4x * 5] = 6(x + 7)
7 + [55 + 20x] = 6(x + 7)

Combine like terms: 7 + 55 = 62
62 + 20x = 6(x + 7)

Reorder the terms:
62 + 20x = 6(7 + x)
62 + 20x = (7 * 6 + x * 6)
62 + 20x = (42 + 6x)

Solving
62 + 20x = 42 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
62 + 20x + -6x = 42 + 6x + -6x

Combine like terms: 20x + -6x = 14x
62 + 14x = 42 + 6x + -6x

Combine like terms: 6x + -6x = 0
62 + 14x = 42 + 0
62 + 14x = 42

Add '-62' to each side of the equation.
62 + -62 + 14x = 42 + -62

Combine like terms: 62 + -62 = 0
0 + 14x = 42 + -62
14x = 42 + -62

Combine like terms: 42 + -62 = -20
14x = -20

Divide each side by '14'.
x = -1.428571429

Simplifying
x = -1.428571429

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